Prab Yuttapichai - Thai actor. Article "ปราบ ยุทธพิชัย" in Thai Wikipedia has 15.6 points for quality (as of August 1, 2024). The article contains 2 references and 9 sections.
In July 2024 the article "ปราบ ยุทธพิชัย" was edited by 2 authors in Thai Wikipedia (2743rd place) and written by 2 authors in all languages.
Since the creation of article "ปราบ ยุทธพิชัย", its content was written by 38 registered users of Thai Wikipedia (3542nd place) and edited by 38 registered Wikipedia users in all languages.
The article is cited 62 times in Thai Wikipedia and cited 62 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from August 1, 2024 (including revision history and pageviews for previous years).
| Best Rank | Thai: #238 07.2024 |
Global: #109745 08.2021 |
On 8 July 2025 in multilingual Wikipedia, Internet users most often read articles on the following topics: Diogo Jota, João Pedro, Ozzy Osbourne, Laura Siegemund, Aryna Sabalenka, Julian McMahon, Jurassic World Rebirth, 2025 FIFA Club World Cup, Amanda Anisimova, F1.
In Thai Wikipedia the most popular articles on that day were: วันอาสาฬหบูชา, องค์การกระจายเสียงและแพร่ภาพสาธารณะแห่งประเทศไทย, วันเข้าพรรษา, พิเศษ:ค้นหา, อสมท, พระบาทสมเด็จพระวชิรเกล้าเจ้าอยู่หัว, คว็อน อึน-บี, จุฬาลงกรณ์มหาวิทยาลัย, พิชัย ชุณหวชิร, ภูมิธรรม เวชยชัย.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from August, 2024. When calculating current popularity and AI of articles data from July 2024 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2023... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(6.73+1.79+0+45+24.44)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
