Article “Перше технічне обслуговування” in Ukrainian Wikipedia has 3.1 points for quality (as of July 1, 2025). The article contains 0 references and 3 sections.
Since the creation of article “Перше технічне обслуговування”, its content was written by 9 registered users of Ukrainian Wikipedia and edited by 9 registered Wikipedia users in all languages.
The article is cited 4 times in Ukrainian Wikipedia and cited 4 times in all languages.
The highest Authors Interest rank from 2001:
The highest popularity rank from 2008:
There is 1 language version for this article in the WikiRank database (of the considered 55 Wikipedia language editions).
The quality and popularity assessment was based on Wikipédia dumps from July 1, 2025 (including revision history and pageviews for previous years).
| Best Rank | Ukrainian: #13005 06.2021 |
Global: #1424858 12.2021 |
| Best Rank | Ukrainian: #3735 03.2010 |
Global: #544696 03.2010 |
On 7 October 2025 in multilingual Wikipedia, Internet users most often read articles on the following topics: Ed Gein, Ilse Koch, Lizzie Borden, Anthony Perkins, Monster: The Ed Gein Story, Greta Thunberg, Richard Speck, Psycho, ChatGPT, Charlie Hunnam.
In Ukrainian Wikipedia the most popular articles on that day were: Бондарєва-Рєпіна Олена Володимирівна, Tomahawk (ракета), Ед Ґейн, Путін Володимир Володимирович, Арестович Олексій Миколайович, Typhon (пускова установка), Шепітько Лариса Юхимівна, Кабаєва Аліна Маратівна, Чудовисько: Історія Еда Ґіна, Вовчанчин Ігор Ярославович.
The WikiRank project is intended for automatic relative evaluation of the articles in the various language versions of Wikipedia. At the moment the service allows to compare over 44 million Wikipedia articles in 55 languages. Quality scores of articles are based on Wikipedia dumps from July, 2025. When calculating current popularity and AI of articles data from June 2025 was taken into account. For historical values of popularity and AI WikiRank used data from 2001 to 2025... More information
$$Quality=1/c∑↙{i=1}↖c nm_i-RS=1/5(2.48+0+0+13.04+0)$$
where:
The results of the calculations may be slightly different because of rounded values of normalized metrics in formulas
